12x^2-30x+16=0

Solution for 12x^2-30x+16=0 equation:

12x^2-30x+16=0

a = 12; b = -30; c = +16;
Δ = b2-4ac
Δ = -302-4·12·16
Δ = 132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132}=\sqrt{4*33}=\sqrt{4}*\sqrt{33}=2\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{33}}{2*12}=\frac{30-2\sqrt{33}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{33}}{2*12}=\frac{30+2\sqrt{33}}{24}
$